3.8 More Trigonometric Identities and Equations (HL)

1. Reciprocal Trigonometric Functions

The HL mathematical architecture formally introduces three critical reciprocal geometries augmenting the foundational ratios.

  • Secant: $\sec\theta = \frac{1}{\cos\theta}$
  • Cosecant: $\csc\theta = \frac{1}{\sin\theta}$
  • Cotangent: $\cot\theta = \frac{1}{\tan\theta} = \frac{\cos\theta}{\sin\theta}$

Geometrically intersecting an independent horizontal boundary tangent above the unit circle exactly at $(0, 1)$ visually plots the cotangent magnitude. Extending the radius mapping angle $\theta$ upwards calculates an identical horizontal displacement strictly equal to $\cot\theta$.

2. Advanced Pythagorean and Compound Identities

Manipulating the fundamental Pythagorean identity $\cos^2\theta + \sin^2\theta = 1$ derives secondary reciprocal structures:

  • Dividing comprehensively by $\cos^2\theta$ produces: $\tan^2\theta + 1 = \sec^2\theta$.
  • Dividing comprehensively by $\sin^2\theta$ produces: $\cot^2\theta + 1 = \csc^2\theta$.

Mathematical calculations dictating compound angle additions or subtractions require complex expansions:

  • $\sin(A \pm B) = \sin A\cos B \pm \cos A\sin B$
  • $\cos(A \pm B) = \cos A\cos B \mp \sin A\sin B$
  • $\tan(A \pm B) = \frac{\tan A \pm \tan B}{1 \mp \tan A\tan B}$

Setting geometric variables $A$ and $B$ mutually identically equal naturally collapses these advanced statements back into fundamental double-angle formulations.

EXAMPLE 2

Perform precise fractional calculations establishing absolute identities for $\sin 75^\circ$ and $\tan 15^\circ$ absent digital evaluation.

Evaluating additive compounds: $\sin 75^\circ = \sin(45^\circ + 30^\circ)$.
Utilizing designated theorem rules evaluates cleanly into: $\sin 45^\circ\cos 30^\circ + \cos 45^\circ\sin 30^\circ$.
Executing numerical conversions guarantees: $\left(\frac{\sqrt{2}}{2}\right)\left(\frac{\sqrt{3}}{2}\right) + \left(\frac{\sqrt{2}}{2}\right)\left(\frac{1}{2}\right) = \mathbf{\frac{\sqrt{6} + \sqrt{2}}{4}}$.
Evaluating subtractive compounds: $\tan 15^\circ = \tan(60^\circ - 45^\circ)$.
Mapping values accurately structures the expression as $\frac{\tan 60^\circ - \tan 45^\circ}{1 + \tan 60^\circ\tan 45^\circ}$.
Numeric insertion dictates purely: $\frac{\sqrt{3} - 1}{1 + \sqrt{3}(1)} = \mathbf{\frac{\sqrt{3} - 1}{\sqrt{3} + 1}}$. (Proper structural rationalization converts this mathematically to $2 - \sqrt{3}$).

3. General Multiple Variable Equalities

Equating two trigonometric states composed identically of nested variable sets (e.g., $\sin A = \sin B$) follows distinct periodic rules dictating complex relationships.

Mathematical Condition Conclusive Relation (Radians)
If $\sin A = \sin B$ $A = B + 2k\pi$
$A = (\pi - B) + 2k\pi$
If $\cos A = \cos B$ $A = B + 2k\pi$
$A = -B + 2k\pi$
If $\tan A = \tan B$ $A = B + k\pi$

Note: The mathematical relationships map exactly into degree formulations by logically substituting $180^\circ$ wherever $\pi$ limits function.

EXAMPLE 3 & 4 (Variable-to-Variable Solutions)

Example 3: Resolve the domain points satisfying $\sin 3x = \sin x$ mapped inside bound limits $0 \le x \le 2\pi$.
Generating absolute formulations dictates two independent structural equations:
$3x = x + 2k\pi \Rightarrow 2x = 2k\pi \Rightarrow x = k\pi$.
$3x = \pi - x + 2k\pi \Rightarrow 4x = \pi + 2k\pi \Rightarrow x = \frac{\pi + 2k\pi}{4}$.
Running iterations constructs conclusive acceptable targets: $\mathbf{x = 0, \pi, 2\pi, \frac{\pi}{4}, \frac{3\pi}{4}, \frac{5\pi}{4}, \frac{7\pi}{4}}$.
Example 4: Determine accurate alignments evaluating $\cos 3x = \cos x$ localized across valid spans $0 \le x \le 2\pi$.
Structural formulations map symmetrically to $3x = x + 2k\pi$ and $3x = -x + 2k\pi$.
Dividing geometrically structures isolated variable solutions: $x = k\pi$ and $x = \frac{k\pi}{2}$.
Because fractional variations fully encapsulate whole intervals, testing purely limits bounds exclusively: $\mathbf{x = 0, \frac{\pi}{2}, \pi, \frac{3\pi}{2}, 2\pi}$.

Converting Mismatched Trigonometric Functions

To safely resolve non-identical comparative functions mapping symmetrically like $\cos A = \sin B$, rigorous translation into matched types fundamentally requires exploiting absolute complementary shift parameters ($90^\circ$ transformations):

$\sin x \equiv \cos\left(\frac{\pi}{2} - x\right)$ and $\cos x \equiv \sin\left(\frac{\pi}{2} - x\right)$

Furthermore, managing adverse operational signs (-), parity characteristics are exploited logically: $\sin(-x) = -\sin x$ (Odd function), $\tan(-x) = -\tan x$ (Odd function), but strictly $\cos(\pi - x) = -\cos x$ (adjusting boundary properties).

EXAMPLE 6 & 7 (Applying Conversions)

Example 6 (Mixed Functions): Solve $\cos 3x = \sin x$ utilizing designated domain $0 \le x \le 2\pi$.
Convert structural elements to uniform type: $\cos 3x = \cos\left(\frac{\pi}{2} - x\right)$.
Establish operational baseline equations:
$3x = \frac{\pi}{2} - x + 2k\pi \Rightarrow 4x = \frac{\pi}{2} + 2k\pi \Rightarrow x = \frac{\pi}{8} + \frac{k\pi}{2}$.
$3x = -\left(\frac{\pi}{2} - x\right) + 2k\pi \Rightarrow 2x = -\frac{\pi}{2} + 2k\pi \Rightarrow x = -\frac{\pi}{4} + k\pi$.
Populating accurate coordinates captures multiple specific domain elements directly conforming to restrictions.
Example 7 (Mixed Signs): Resolve equations calculating $\sin 3x = -\sin x$ operating over bounds spanning $0 \le x \le 2\pi$.
Invert properties algebraically capturing negative values integrally: $\sin 3x = \sin(-x)$.
Establish operational baseline mappings:
$3x = -x + 2k\pi \Rightarrow 4x = 2k\pi \Rightarrow x = \frac{k\pi}{2}$.
$3x = \pi - (-x) + 2k\pi \Rightarrow 2x = \pi + 2k\pi \Rightarrow x = \frac{\pi}{2} + k\pi$.
Iterative testing filters exact geometric matches uniformly bounded securely.

EXAMPLE 8 (Resolving Reciprocal Equations)

Assess constraints solving logically $\sec x = 2$.

Solution: The reciprocal formulation immediately translates strictly into fundamental terms evaluating $\cos x = 1/2$. Executing universal processes calculates bounded sets $\mathbf{x = \pm\frac{\pi}{3} + 2k\pi}$ corresponding exactly to $\mathbf{x = \pm 60^\circ + 360^\circ k}$.