3.4 The Trigonometric Circle - Arcs and Sectors

1. Concept of the Trigonometric Circle

The trigonometric circle geometrically maps angle values onto a 360-degree continuous boundary. Starting securely from the positive x-axis and rotating anticlockwise maps positive orientations ($0^\circ, 90^\circ, 180^\circ, 270^\circ, 360^\circ$). Rotating physically clockwise dictates mathematically negative values ($-90^\circ$ acts identically to $270^\circ$).

Periodic properties allow angles extending far past $360^\circ$ to functionally overlap points on the initial cycle. The general position on the boundary is maintained exactly through the expression $\theta \pm 360^\circ k$ (where $k$ is any integer multiple).

2. Degrees and Radians

Radians act as an alternative unit of measurement correlating geometrically directly to the perimeter arc length traced along a pure unit circle ($r=1$). A full $360^\circ$ revolution traces precisely the complete circumference distance $2\pi$.

Degrees $0^\circ$ $90^\circ$ $180^\circ$ $270^\circ$ $360^\circ$
Radians $0$ $\frac{\pi}{2}$ $\pi$ $\frac{3\pi}{2}$ $2\pi$

Conversion Formula: The proportional ratio mapping degrees to radians is $\frac{\text{Degrees}}{180^\circ} = \frac{\text{Radians}}{\pi}$.

EXAMPLE 1 & 2 (Unit Conversions)

Transform into Radians (Example 1):
$\theta_1 = 30^\circ \Rightarrow \frac{30^\circ}{x} = \frac{180^\circ}{\pi} \Rightarrow x = \mathbf{\frac{\pi}{6}\text{ rad}}$.
$\theta_2 = 80^\circ \Rightarrow \frac{80^\circ}{x} = \frac{180^\circ}{\pi} \Rightarrow x = \mathbf{\frac{4\pi}{9}\text{ rad}}$.
$\theta_3 = 27^\circ \Rightarrow x = \mathbf{0.471\text{ rad}}$.
Transform into Degrees (Example 2):
$\theta_1 = \frac{\pi}{3} \Rightarrow \frac{x}{\pi/3} = \frac{180^\circ}{\pi} \Rightarrow x = \mathbf{60^\circ}$.
$\theta_2 = \frac{4\pi}{9} \Rightarrow \frac{x}{4\pi/9} = \frac{180^\circ}{\pi} \Rightarrow x = \mathbf{80^\circ}$.
$\theta_3 = 2 \text{ rad} \Rightarrow \frac{x}{2} = \frac{180^\circ}{\pi} \Rightarrow x = \frac{360}{\pi} = \mathbf{114.6^\circ}$.

3. Length of Arcs and Area of Sectors

Given a circle possessing radius $r$ and a central interior angle denoted as $\theta$ (must strictly be measured in radians):

  • Length of Arc ($L$): $L = r\theta$
  • Area of Sector ($A$): $A = \frac{1}{2}r^2\theta$

Note: The area isolated structurally between a chord line segment AB and the circular arc boundary AB (a geometric segment) is given by $A_{\text{segment}} = \frac{1}{2}r^2(\theta - \sin\theta)$.

EXAMPLE 3

Consider a bounded sector characterized by radius $r = 5\text{m}$ and angle $\theta = 0.6\text{ rad}$.

Length of circular arc: $L = 5 \times 0.6 = \mathbf{3\text{m}}$.
Area of bound sector: $A = \frac{1}{2}(5^2)(0.6) = \mathbf{7.5\text{m}^2}$.
Perimeter surrounding sector: $L + r + r = 3 + 5 + 5 = \mathbf{13\text{m}}$.

EXAMPLE 4

Given geometric parameters $r = 3\text{cm}$ and $\theta = 30^\circ$, evaluate dimensional features.

First, structurally convert degrees to radians: $\theta = \frac{\pi}{6}\text{ rad}$.
(a) Arc length AB: $L = 3\left(\frac{\pi}{6}\right) = \frac{\pi}{2} \approx \mathbf{1.57\text{cm}}$.
(b) Sector Area OAB: $A_{\text{sec}} = \frac{1}{2}(3^2)\left(\frac{\pi}{6}\right) = \frac{3\pi}{4} \approx \mathbf{2.36\text{cm}^2}$.
(c) Straight distance AB (chord length): Utilizing Cosine Rule evaluating the full triangle:
$AB^2 = 3^2 + 3^2 - 2(3)(3)\cos\left(\frac{\pi}{6}\right) \Rightarrow AB \approx \mathbf{1.55\text{cm}}$.
(d) Area of triangle OAB: $A_{\text{tri}} = \frac{1}{2}(3)(3)\sin\left(\frac{\pi}{6}\right) = \mathbf{2.25\text{cm}^2}$.