3.11 Vectors: Algebraic Representation (HL)
1. 2-Dimensional Algebraic Vectors
A vector $\vec{u}$ is formally expressed algebraically as a column matrix containing its directional components: $\binom{a}{b}$.
EXAMPLE 1 & 2 (Algebraic Operations)
Given vectors $\vec{u} = \binom{3}{4}$ and $\vec{v} = \binom{2}{5}$:
2. Unit Vectors and Base Notation
The Unit Vector: A unit vector $\hat{u}$ is a specialized vector possessing a magnitude of exactly 1, pointing precisely in the same direction as $\vec{u}$. It is calculated by dividing the vector by its own magnitude:
EXAMPLE 3
Establish a vector $\vec{a}$ parallel to $\vec{u} = \binom{3}{4}$ possessing a strict magnitude of 20.
Standard Base Vectors ($\vec{i}$ and $\vec{j}$):
Any 2D vector can be expressed as a linear combination of the fundamental unit vectors tracing the x-axis and y-axis. Defining $\vec{i} = \binom{1}{0}$ and $\vec{j} = \binom{0}{1}$, the column vector $\binom{a}{b}$ translates algebraically to $a\vec{i} + b\vec{j}$.
3. 3-Dimensional Vectors and Point Mapping
Expanding into 3D space introduces a third vertical $z$-axis component. Vectors formulate as $\binom{a}{b}{c}$ or algebraically as $a\vec{i} + b\vec{j} + c\vec{k}$. The magnitude scales identically: $|\vec{u}| = \sqrt{a^2 + b^2 + c^2}$.
EXAMPLE 4
Evaluate operations for $\vec{u} = \binom{1}{2}{3}$ and $\vec{v} = \binom{2}{5}{-4}$.
Vector Mapping Between Points
The directional vector spanning from point $A(x_1, y_1, z_1)$ to point $B(x_2, y_2, z_2)$ is mathematically extracted by subtracting the position vector of the origin tail ($A$) from the position vector of the destination head ($B$):