2.6 Transformations of Functions
1. Vertical Transformations
Vertical manipulations alter the outputs ($y$-values) and occur strictly "outside" the primary function evaluation. Assume $a > 0$ and $b > 1$.
| Notation | Geometric Transformation |
|---|---|
| $f(x) + a$ | Vertical translation $a$ units up |
| $f(x) - a$ | Vertical translation $a$ units down |
| $b \cdot f(x)$ | Vertical stretch by a scale factor of $b$ |
| $f(x) / b$ | Vertical stretch by a scale factor of $1/b$ (shrink) |
| $-f(x)$ | Reflection across the x-axis |
2. Horizontal Transformations
Horizontal manipulations alter the inputs ($x$-values) and occur strictly "inside" the function bracket. These operations act counter-intuitively.
| Notation | Geometric Transformation |
|---|---|
| $f(x + a)$ | Horizontal translation $a$ units to the left |
| $f(x - a)$ | Horizontal translation $a$ units to the right |
| $f(bx)$ | Horizontal stretch by a scale factor of $1/b$ (shrink) |
| $f(x/b)$ | Horizontal stretch by a scale factor of $b$ |
| $f(-x)$ | Reflection across the y-axis |
EXAMPLE 2 (Point Translations)
Let $A(6, 10)$ be a coordinate situated on the curve $y = f(x)$. Applying discrete transformations yields new coordinate pairs $A'$:
3. Composite Transformations
Vector Notation: A horizontal translation $a$ and vertical translation $b$ combined can be strictly defined utilizing the translation vector $\binom{a}{b}$. For the quadratic vertex form $y=a(x-h)^2+k$, the base parabola shifts by the translation vector $\binom{h}{k}$.
Order of Execution: The specific order applied to composite sequences dictates algebraic accuracy.
- For vertical $y = 2f(x) + 3$, stretch by 2 first, then translate up by 3. Reversing the execution creates $2[f(x) + 3] = 2f(x) + 6$.
- For horizontal $y = f(2x + 6)$, evaluate input changes relative to $x$. Expressing as $f(2(x+3))$ accurately reveals a horizontal shrink by factor $1/2$, followed by a translation left by 3.